Two angles of a quadrilateral measure 85° and 75° respectively. The other two angles are equal. Find the measure of each of these equal angles.
Let x be the common angle of quadrilateral.
As per question,
A = 85°
B = 75°
C =
D = x
As we know that, Sum of all four angles of quadrilateral is 360o.
A +
B +
C +
D = 360°
85° + 75°+ x + x = 360°
2x = 360° - (85° + 75°)
2x = 200°
X = 200 / 2
= 100°
C =
D = 100°
So, Two angles of quadrilateral whose measuring’s are equal is 100°.