##### In a single throw of two coins, find the probability of getting (i) both tails, (ii) at least 1 tail,(iii) at the most 1 tail.

(i) A coin has two sides a head(H) and a tail(T), and there are two such coins.

There are Xm possible outcomes.

That is 22 = 4 and they are HH, HT, TH, TT

All possible outcomes are HH, HT, TH, TT.

Total number of outcomes = 4

Chances of getting 2 tails = 1, that is TT

Probability P() =

Probability of getting a tail P(both T) = =

(ii) A coin has two sides a head(H) and a tail(T), and there are two such coins.

There are Xm possible outcomes.

That is 22 = 4 and they are HH, HT, TH, TT

All possible outcomes are HH, HT, TH, TT.

Total number of outcomes = 4

Chances of getting atleast one tail = 3, that is HT, TH, TT.

Probability P() =

Probability of getting a tail P(atleast 1 T) = =

(iii) A coin has two sides a head(H) and a tail(T), and there are two such coins.

There are Xm possible outcomes.

That is 22 = 4 and they are HH, HT, TH, TT

All possible outcomes are HH, HT, TH, TT.

Total number of outcomes = 4

Chances of getting atmost 1 tail = 3, that is HT, TH, TT.

Probability P() =

Probability of getting a tail P(atmost 1 T) = =

3