It is known that a box of 100 electric bulbs contains 8 defective bulbs. One bulb is taken out at random from the box. What is the probability that the bulb drawn is (i) defective? (ii) non-defective?
(i) Total number of electric bulbs = 100
Number of defective bulbs = 8
Probability P() = 
Probability of getting a defective bulbs P(d bulbs) = 
= 
= 
(ii) Total number of electric bulbs = 100
Number of Non-defective bulbs = 100-8 = 92 (Number of electric bulbs – Number of defective bulbs)
Probability P() = 
Probability of getting a Non- defective bulbs P(bulbs) = 
= 
= 
7