If 64y8 is exactly divisible by 3, then the least value of y is

We know that if sum of digits of a number is divisible by 3, then the number is divisible by 3.


Here,


6 + 4 + y + 8 = multiple of 3


18 + y = 0, 3, 6, 9, ….


Hence,


18 + y = 18


y = 0


the least value of y is 0.

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