If x7y5 is exactly divisible by 3, then the least value of (x + y) is
We know that if sum of digits of a number is divisible by 3, then the number is divisible by 3.
Here,
x + 7 + y + 5 = multiple of 3
x + y + 12 = 0, 3, 6, 9, ….
Hence,
x + y + 12 = 12
∴ x + y = 0
But x + y cannot be 0 because then x and y both will have to be 0.
Since x is the first digit, it cannot be 0.
∴ x + y + 12 = 15
x + y = 3
∴ the least value of (x + y) is 3