If 1A2B5 is exactly divisible by 9, then the least value of (A + B) is
We know that if sum of digits of a number is divisible by 9, then the number is divisible by 9.
Here,
1 + A + 2 + B + 5 = multiple of 9
A + B + 8 = 0, 9, 18, ….
Hence,
A + B + 8 = 9
A + B =1