If 1A2B5 is exactly divisible by 9, then the least value of (A + B) is

We know that if sum of digits of a number is divisible by 9, then the number is divisible by 9.


Here,


1 + A + 2 + B + 5 = multiple of 9


A + B + 8 = 0, 9, 18, ….


Hence,


A + B + 8 = 9


A + B =1

8