If the 4-digit number x27y is exactly divisible by 9, then the least value of (x + y) is

We know that if sum of digits of a number is divisible by 9, then the number is divisible by 9.


Here,


x + 2 + 7 + y = multiple of 9


x + y + 9= 0, 9, 18, …


Hence,


x + y + 9 = 9


x + y =0


But x + y cannot be 0 because then x and y both will have to be 0.
Since x is the first digit, it cannot be 0.
x + y + 9 = 18


x + y = 9


the least value of (x + y) is 9

9