If the 4-digit number x27y is exactly divisible by 9, then the least value of (x + y) is
We know that if sum of digits of a number is divisible by 9, then the number is divisible by 9.
Here,
x + 2 + 7 + y = multiple of 9
x + y + 9= 0, 9, 18, …
Hence,
x + y + 9 = 9
∴ x + y =0
But x + y cannot be 0 because then x and y both will have to be 0.
Since x is the first digit, it cannot be 0.
∴ x + y + 9 = 18
x + y = 9
∴ the least value of (x + y) is 9