If 7 × 8 is exactly divisible by 3, then the least value of x is

We know that if sum of digits of a number is divisible by 3, then the number is divisible by 3.


Here,


7 + x + 8 = multiple of 3


x + 15 = 0, 3, 6, 9, ….


Hence,


x + 15 = 15


x = 0


the least value of x is 0

8