If 7 × 8 is exactly divisible by 3, then the least value of x is
We know that if sum of digits of a number is divisible by 3, then the number is divisible by 3.
Here,
7 + x + 8 = multiple of 3
x + 15 = 0, 3, 6, 9, ….
Hence,
x + 15 = 15
x = 0
∴ the least value of x is 0