The dimensions of a room are (10 mx8mx 3.3 m). How many men can be accommodated in this room if each man requires 3 m3 of space?
We know that,
Volume of a cuboid = Length × Breadth × Height
Therefore,
Volume of the room = 10 × 8 × 3.3
= 264 m3
Space required by 1 person = 3 m3
Therefore,
Total number of people that can be accommodated = 
= 88
Hence, option B is correct
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