In a trapezium-shaped field, one of the parallel sides is twice the other. If the area of the field is 9450 m2 and the perpendicular distance between the two parallel sides is 84 m, find the length of the longer of the parallel sides.
Given
Let length of first parallel side X
Length of other parallel side is 2X
Area of trapezium= 9450 m2
Let Height (h) =84 m
We know that area of trapezium is × (sum of parallel sides) × height
Therefore Area of trapezium is × (X + 2X) × 84 =9450 cm2.
× (X + 2X) × 84 =9450
⇒ (3X) × 42 =9450
⇒ 126X = 9450
⇒ 2X + 6 = = 75
⇒X = 17
... Length of the parallel sides is X=75 m and 2X = 150 m.
Therefore length of the longest is 150 m.