Find the area enclosed by the given figure ABCDEF as per dimensions given herewith.

Given: A figure ABCDEF


AB = 20 cm


BC = 20 cm


ED = 6 cm


AF = 20 cm


AB || FC


FC = 20 cm


Let distance between FC and ED be h = 8 cm


FC || ED


Here,


From the figure we can see that ABCF forms a square and EFCD forms a trapezium.


Area of square = (side length) 2


Area of trapezium = × (sum of parallel sides) × height


Therefore,


Area of the figure ABCDEF = Area of square (ABCF) + Area of trapezium (EFCD)


Here,


Area of square (ABCF) = (AB) 2 = (20)2 = 400 cm2


Area of trapezium (EFCD) = × (FC + ED) × h = × (6 + 20) × 8 = 104 cm 2


Area (ABCDEF) = Area of square (ABCF) + Area of trapezium (EFCD) = 400 + 104 = 504 cm2.


Area (Fig. ABCDEF) = 504 cm2.


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