The perimeter of a rhombus is 180 cm and one of its diagonals is 72 cm. Find the length of the other diagonal and the area of the rhombus.
Given: A rhombus
Diagonal AC = 72 cm
Perimeter = 180 cm
Perimeter of the rhombus = 4x
Therefore 4x = 180
x= 45
hence, the side length of the rhombus is 45 cm
We know that diagonals of the rhombus bisect each other right angles.
AO =
AC
⇒AO = ( × 72) cm
⇒AO = 36 cm
From right AOB, we have :
BO2 = AB2 – AO2
⇒BO2 = AB2 – AO2
⇒BO2 = 452 – 362
⇒BO2 = 2025 – 1296
⇒BO2 = 729
BO = 27 cm
BD = 2× BO
BD = 2 × 27 = 54 cm
Hence, the length of the other diagonal is 54 cm.
Area of the rhombus = × 72 × 54 = 1944 cm2