from the equation of motion

s= ut + at² Distance travelled in 5s,

s = u x 5+ x a x (5)²

s =5u + 25/2 a …….(i)

Similarly, distance travelled in 4s,

s’ =4u +16/2 a

s’ =4u+8a…….(ii)

Distance travelled in the interval between 4^th and 5^th second=(s-s’)

= (5u +25/2 – 4u +8)

= (u+ a) m