An elevator descends into a mine shaft at the rate of 6 m/min. If the descent starts form 10m above the ground level, how long will it take to reach – 350 m

In the above question the distance descended is denoted by a negative integer

It is given in the question that,

Initial height = 10 m

Also,

Final depth = - 350 m

Therefore,

Total distance to be descended by the elevator = (-350) – (10)

= - 360 m

Also,

Time taken by the elevator to descend – 6m = 1 minute

Hence,

Time taken by the elevator to descend – 360 m =

= 60 minutes

= 1 hour

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