An elevator descends into a mine shaft at the rate of 6 m/min. If the descent starts form 10m above the ground level, how long will it take to reach – 350 m

In the above question the distance descended is denoted by a negative integer


It is given in the question that,


Initial height = 10 m


Also,


Final depth = - 350 m


Therefore,


Total distance to be descended by the elevator = (-350) – (10)


= - 360 m


Also,


Time taken by the elevator to descend – 6m = 1 minute


Hence,


Time taken by the elevator to descend – 360 m =


= 60 minutes


= 1 hour


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