Find the value of the unknown x in the following diagrams:
(i) In the above question, we have
1st interior angle = x, 2nd interior angle = 50o and 3rd interior angle = 60o
We have to find out the value of x
Thus,
x + 50o + 60o = 180o (angle sum property of triangle)
x + 110o = 180o
x = 180o – 110o
x = 70o
Hence, the value of x is 70o
(ii) In the above question, we have
1st interior angle = x, 2nd interior angle = 90o and 3rd interior angle = 30o
We have to find out the value of x
Thus,
x + 90o + 30o = 180o (angle sum property of triangle)
x + 120o = 180o
x = 180o – 120o
x = 60o
Hence, the value of x is 60o
(iii) In the above question, we have
1st interior angle = x, 2nd interior angle = 30o and 3rd interior angle = 110o
We have to find out the value of x
Thus,
x + 30o + 110o = 180o (angle sum property of triangle)
x + 140o = 180o
x = 180o – 140o
x = 40o
Hence, the value of x is 40o
(iv) In the above question, we have
1st interior angle = 50o, 2nd interior angle = xand 3rd interior angle = x
We have to find out the value of x
Thus,
50o + x + x = 180o (angle sum property of triangle)
2x + 50o = 180o
2x = 180o – 50o
2x = 130o
x =
x = 65o
Hence, the value of x is 65o
(v) In the above question, we have
1st interior angle = x, 2nd interior angle = x and 3rd interior angle = x
We have to find out the value of x
And,
x + x + x = 180o (angle sum property of triangle)
3x = 180o
x =
x = 60o
Hence, the value of x is 60o
(vi) In the above question, we have
1st interior angle = x, 2nd interior angle = 2x and 3rd interior angle = 90o
We have to find out the value of x
Thus,
x + 2x + 90o = 180o (angle sum property of triangle)
3x + 90o = 180o
3x = 180o – 90o
3x = 90o
x =
x = 30o
Hence, the value of x is 30o