Angles Q and R or a PQR are 25^{o} and 65^{o}. Write which of the following is true:

(i) PQ^{2} + QR^{2}= RP^{2}

(ii) PQ^{2} + RP^{2}= QR^{2}

(iii) RP^{2} + QR^{2}= PQ^{2}

In the above question, it is given that:

In PQR, we have

∠Q = 25^{o} and ∠R = 65^{o}

We know that,

The sum of interior angles of a triangle = 180^{o}

∠PQR + ∠PRQ + ∠QPR = 180^{o}

25^{o} + 65^{o} + ∠QPR = 180^{o}

90^{o} + ∠QPR = 180^{o}

∠QPR = 180^{o} – 90^{o}

= 90^{o}

Hence, is right angled at point P

Thus,

By using Pythagoras theorem, we get:

(PR)^{2} + (PQ)^{2} = (QR)^{2}

Hence,

Option (ii) is true

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