Angles Q and R or a PQR are 25o and 65o. Write which of the following is true:


(i) PQ2 + QR2= RP2


(ii) PQ2 + RP2= QR2


(iii) RP2 + QR2= PQ2


In the above question, it is given that:


In PQR, we have


∠Q = 25o and ∠R = 65o


We know that,


The sum of interior angles of a triangle = 180o


∠PQR + ∠PRQ + ∠QPR = 180o


25o + 65o + ∠QPR = 180o


90o + ∠QPR = 180o


∠QPR = 180o – 90o


= 90o


Hence, is right angled at point P


Thus,


By using Pythagoras theorem, we get:


(PR)2 + (PQ)2 = (QR)2


Hence,


Option (ii) is true

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