ABC is isosceles with AB = AC = 7.5 cm and BC = 9 cm. The height AD from A to BC, is 6 cm. Find the area of 
ABC. What will be the height from C to AB i.e., CE?
It is given in the question that,
ABC is isosceles triangle
AB = AC = 7.5 cm
BC = 9 cm
Height AD from A to BC = 6 cm
We know that,
Area of triangle = 
× Base × Height
∴ Area of 
ABC = 
× BC × AD
= 
× 9 × 6
= 27 cm2
Area of 
ABC = 
× Base × Height
27 = 
× 7.5 × CE
54 = 7.5 × CE
CE = 
= 7.2 cm
Hence,
The height from C to AB = CE = 7.2 cm
26