ABC is isosceles with AB = AC = 7.5 cm and BC = 9 cm. The height AD from A to BC, is 6 cm. Find the area of ABC. What will be the height from C to AB i.e., CE?

It is given in the question that,

ABC is isosceles triangle

AB = AC = 7.5 cm

BC = 9 cm

Height AD from A to BC = 6 cm

We know that,

Area of triangle = × Base × Height

∴ Area of ABC = × BC × AD

= × 9 × 6

= 27 cm^{2}

Area of ABC = × Base × Height

27 = × 7.5 × CE

54 = 7.5 × CE

CE =

= 7.2 cm

Hence,

The height from C to AB = CE = 7.2 cm

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