A verandah of width 2.25 m is constructed all along he outside a room which is 5.5 m long and 4 m wide.

Find:

(i) The area of the verandah

(ii) The cost of cementing the floor of the verandah at the rate of Rs. 200 per m^{2}.

(i) It is given in the question that,

Length of room = 5.5 m

Breadth of room = 4 m

We know that,

Area of rectangle = Length × Breadth

∴ Area of room = 5.5 × 4

= 22 m^{2}

From the figure it can be observed that the new length and breadth of the given room (When verandah is included) is 10 m and 8.5 m respectively

∴ Area of room including verandah = 10 × 8.5

= 85 m^{2}

Area of verandah = Area of the room including verandah – Area of room

= 85 – 22

= 63 m^{2}

(ii) It is also given in the question that,

Cost of cementing 1 m^{2} area of the floor of the verandah = Rs 200

∴ Cost of cementing 63 m^{2} area of the floor of the verandah = 200 × 63

= Rs 12600

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