Set up equations and solve them to find the unknown numbers in the following cases:

(a) Add 4 to eight times a number you get 60.


(b) One-fifth of a number minus 4 gives 3.


(c) If I take three-fourths of a number and add 3 to it, I get 21.


(d) When I subtracted 11 from twice a number, the result was 15.


(e) Munna subtracts thrice the number of


(f) Notebooks he has from 50, he finds the result to be 8.


(g) Ibenhal thinks of a number. If she adds 19 to it and divides the sum by 5, she will get 8.


(h) Anwar thinks of a number. If he takes away 7 from of the number, the result is 23.

The parts of this given questions are solved below:


(a) We have to frame the equation on the basis of given statement


And then solve the so framed equation


Thus,


Let the number be a


We know that,


Eight times of a is 8a


Therefore,


As per the statement,


We can write the equation as,


8a + 4 = 60


8a = 60 – 4


8a = 56


Now,


Dividing 8 on both the sides, we get



Therefore,


a = 7


(b) We have to frame the equation on the basis of given statement


And then solve the so framed equation


Thus,


Let the number be a


We know that,


One fifth of a is


Therefore,


As per the statement,


We can write the equation as,



= 3 + 4


= 7


Now,


Multiplying 5 to both the sides, we get



Therefore,


a = 35


(c) We have to frame the equation on the basis of given statement


And then solve the so framed equation


Thus,


Let the number be a


We know that,


Three fourth of a is


Therefore,


As per the statement,


We can write the equation as,



= 21 – 3


= 18


Now,


Multiplying to both the sides, we get



Therefore,


a = 24


(d) We have to frame the equation on the basis of given statement


And then solve the so framed equation


Thus,


Let the number be a


We know that,


Twice of a is 2a


Therefore,


As per the statement,


We can write the equation as,


2a – 11 = 15


2a = 15 + 11


2a = 26


Now,


Dividing 2 on both the sides, we get



Therefore,


a = 13


(e) We have to frame the equation on the basis of given statement


And then solve the so framed equation


Thus,


Let the number be a


We know that,


Thrice of a is 3a


Therefore,


As per the statement,


We can write the equation as,


50 – 3a = 8


-3a = 8 – 50


-3a = -42


Now,


Dividing -3 on both the sides, we get



Therefore,


a = 14


(f) We have to frame the equation on the basis of given statement


And then solve the so framed equation


Thus,


Let the number be a


Therefore,


As per the statement,


We can write the equation as,



Now,


Multiplying 5 to both the sides, we get



Therefore,


a + 19 = 40


a = 40 – 19


a = 21


(g) We have to frame the equation on the basis of given statement


And then solve the so framed equation


Thus,


Let the number be a


We know that,


of a is


Therefore,


As per the statement,


We can write the equation as,



= 23 + 7


= 30


Now,


Multiplying to both the sides, we get



Therefore,


a = 12


13