Here,

According to the question,

We have to draw figure using following steps of construction:

Step 1: Draw a line segment QR of 3.5 cm.

Step 2: Taking Q as a center and radius 4 cm mark an arc.

Step 3: Now, taking R as a center and radius 4 cm mark another arc intersecting the previous arc at P.

Step 4: Join Q to P and R to P

Hence ΔPQR is the required triangle.

Since the two sides (PQ and PR) have same length i.e. 4cm.

Thus, ΔPQR is an isosceles triangle.