Here,

According to the question,

We have to draw figure using following steps of construction:

Step 1: Draw a line segment QR of 8 cm

Step 2: Now, From Q construct a ray QX making an angle of 90° with QR.

Step 3: Take R as a center and radius of 10cm draw an arc intersecting QX at P

Step 4: Now, join RP

Hence, ΔPQR is the required triangle.