Construct an/isosceles right-angled triangle ABC, where m ∠ACB =90^{o} and AC = 6cm.

Here,

According to the question,

We have to draw figure using following steps of construction:

Step 1: Draw a line segment AC of 6 cm

Step 2: Now, From C construct a ray CX making an angle of 90° with AC.

Step 3: Take C as a centre and radius of 6cm draw an arc intersecting CX at B

Step 4: Now, join AB

Hence, ΔABC is the required triangle.

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