##### Express the number appearing in the following statements in standard form.(a) The distance between Earth and Moon is 384,000,000 m.(b) Speed of light in vacuum is 300,000,000 m/s.(c) Diameter of the Earth is 1,27,56,000 m.(d) Diameter of the Sun is 1,400,000,000 m.(e) In a galaxy there are on an average 100,000,000,000 stars.(f) The universe is estimated to be about 12,000,000,000 years old.(g) The distance of the Sun form the centre of the Milky Way Galaxy is estimated to be 300,000,000,000,000,000,000 gm.(h) 60,230, 000,000,000,000,000,000 molecules are contained in a drop of water weighting 1.8 gm.(i) The earth has 1,353,000,000 cubic km of sea water.(j) The population of India was about 1,027,000,000 in March, 2001

(a) It is given that,

Distance between Earth and Moon = 384, 000, 000 m

Thus,

384, 000, 000 = 3.84 × 108 m

(b) It is given that,

Speed of light in vacuum = 300, 000, 000 m/s

Thus,

300, 000, 000 = 3 × 108 m/s

(c)It is given that,

Diameter of Earth = 1, 27, 56, 000 m

Thus,

1, 27, 56, 000 = 1.2756 × 107 m

(d) It is given that,

Diameter of Sun = 1, 400, 000, 000 m

Thus,

1, 400, 000, 000 = 1.4 × 109 m

(e) It is given that,

Average number of stars in galaxy = 100, 000, 000, 000 stars

Thus,

100, 000, 000, 000 = 1 × 1011 stars

(f) It is given that,

Estimated age of universal = 12, 000, 000, 000 years

Thus,

12, 000, 000, 000 = 1.2 × 1010 years

(g) It is given that,

Distance of sun from the centre of Milky Way galaxy = 300, 000, 000, 000, 000, 000, 000 m

Thus,

300, 000, 000, 000, 000, 000, 000 = 3 × 1020 m

(h) It is given that,

Total number of molecules in a drop of water weighing 1.8 gram = 60, 230, 000, 000, 000, 000, 000, 000 m

Thus,

60, 230, 000, 000, 000, 000, 000, 000 = 6.023 × 1022

(i) It is given that,

Area of sea water on earth = 1, 353, 000, 000 cubic km

Thus,

1, 353, 000, 000 = 1.353 × 109 cubic km

(j) It is given that,

Population of India in March 2001= 1, 027, 000, 000

Thus,

1, 027, 000, 000 = 1.027 × 109

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