How much solar energy will be received by 1 m2 area in one hour if the solar constant be 1.4 kW/m2?
From the solar constant we deduce that
1.4 kW of power is incident upon every 1m2 of area.
i.e the total energy incident in 1 hr over an area of 1 m2 will be = 1.4 kW x 1 hr
(Since P=E/t or E=P x t)
Hence, energy = 1.4 kWh
Solar energy received by 1 m2 area in one hour (or 3600 s) = 1.4 x 3600 = 5040 kJ