Factories:

i. 14x3 + 21x4y – 28x2y2


ii. - 5 – 10t + 20t2

(i) Let’s find out the HCF of 14x3, 21x4y and 28x2y2


7x2



14x3, 21x4y, 28x2y2




2x, 3x2y, 4y2



7x2 is the highest common factor of 14x3, 21x4y, 28x2y2


So,


14x3 + 21x4y – 28x2y2 = 7x2(2x + 3x2y – 4y2)


(ii) Let’s find out the HCF of 5, 10t and 20t2,


5



5, 10t, 20t2




1, 2t, 4t2



5 is the highest common factor of 5, 10t and 20t2.


So,


- 5 – 10t + 20t2 = - 5(1 + 2t – 4t2)


(Note: As we have learned in the previous chapter when we multiplied – sign with – sign it become +)


5