Solve:


Taking LCM of 5 and 2 = 10 on LHS and LCM of 3 and 1 = 3 on RHS



By cross multiplication


3(4x + 14 - 15x - 55) = 10(2x - 7)


3( - 11x - 41) = 20x - 70


- 33x - 20x = 123 - 70



11