An altitude of a triangle is five - thirds the length of its corresponding base. If the altitude be increased by 4 cm and the base decreased by 2 cm, the area of the triangle remains the same. Find the base and the altitude of the triangle.
Let the length of the altitude and base of a triangle be l cm and b cm
According to the question
(A)
Area of a triangle
And
Putting (A) we get
Taking LCM of 3 and 1 = 3 on LHS
⇒ 2b = 24 cm