Find the value of each of the following using the short-cut method:
(25)3
Let’s take, a = 2 and b = 5
So, by using the formula,
We have a3+3a2b+3ab2+b3
4 × 2 | 4 × 15 | 25 × 6 | 25 × 5 |
8 +7 | 60 +16 | 150 +12 | 125 |
15 | 76 | 162 |
Keep the digits
By taking the highlighted digits only,
We get;
؞ (25)3 = 15625