Which of the following numbers is a perfect cube?
Having prime factors of all the numbers we get,
=
4
(not a perfect cube)
11 | 1331 |
11 | 121 |
11 | 11 |
1 |
=
(perfect cube)
=
(not a perfect cube)
= no prime factors are possible
Hence, only case of 1331 a perfect triplet pair of 11’s is formed, Hence 1331 is a perfect cube.