Which of the following numbers is a perfect cube?

From the prime factorization of 121, we get,


11



121



11



11




1



121 = 11 × 11


13



169



13



13




1



169 = 13 × 13


2



196



2



98



7



49



7



7




1



196 = 2 × 2 × 7 × 7 = 14 × 14


2



216



2



108



2



54



3



27



3



9



3



3




1



216 = 2 × 2 × 2 × 3 × 3 × 3 = 2 × 3 = 6


Hence, in case of 216 perfect triplet pairs of 2’s and 3’s is formed, so 216 is a perfect cube.

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