Which of the following numbers is a perfect cube?
From the prime factorization of 121, we get,
11 | 121 |
11 | 11 |
1 |
121 = 11 × 11
13 | 169 |
13 | 13 |
1 |
169 = 13 × 13
2 | 196 |
2 | 98 |
7 | 49 |
7 | 7 |
1 |
196 = 2 × 2 × 7 × 7 = 14 × 14
2 | 216 |
2 | 108 |
2 | 54 |
3 | 27 |
3 | 9 |
3 | 3 |
1 |
216 = 2 × 2 × 2 × 3 × 3 × 3 = 2 × 3 = 6
Hence, in case of 216 perfect triplet pairs of 2’s and 3’s is formed, so 216 is a perfect cube.