Construct a quadrilateral ABCD in which AB=5.6cm, BC=4cm, ∠A= 50°, ∠B = 105° and ∠D = 80°.
∠C = 360° - (∠A + ∠B + ∠D)
= 360° - (50° + 105° + 80°)
= 125°
The given quadrilateral ABCD can be drawn as follows:
Step 1: Draw a line segment AB = 5.6 cm
Step 2: At B, draw an angle BCC’ of measure 125° using protractor
Step 3: With C as centre draw an arc on CC’ for BC = 4cm.
Step 4: At D, draw an angle of measure 80° using a protractor.
Step 5: At B, draw an angle BCC’ of measure 105° using protractor DD’ to cut at A.
Step 6: ABCD is the required quadrilateral.