36^o,72^o,108^o,144^o

Let x be the common multiple.

As per question,

A = x

B = 2x

C = 3x

D = 4x

As we know that, Sum of all four angles of quadrilateral is 360^o.

A + B + C + D = 360°

x + 2x + 3x + 4x = 360°

10x = 360°

X= 360/10

= 36°

A = 1 X 36° = 36°

B = 2 X 36° = 72°

C = 3 X 36° = 108°

D = 4 X 36° = 144°

So, Angles of quadrilateral are 36°, 72°, 108° and 144°.