A = 72°,B = 108°,C = 72°,D = 108°

Let x be the common multiple.

As per question,

A = 2x

B = 3x

C = 2x

D = 3x

A + B = 180° (Adjacent angles of parallelogram is supplementary)

2x + 3x = 180°

5x = 180°

X = 180 / 5 = 36°

A = 2 × 36° = 72°

B = 3 × 36° = 108°

C = 2 × 36° = 72°

D = 3 × 36° = 108°

So, Angles of quadrilateral are 72°, 108°, 72° and 108°.