When p (x) = x3 – ax2 + x is divided by (x – a), the remainder is
We have,
x3 – ax2 + x
Let, p (x) = x3 – ax2 + x
And, x - a = 0
x = a
It is given that, (x - a) is a factor of p (x) so the remainder is equal to p (a)
∴ p (a) = (a)3 – a (a)2 + a
= a3 – a3 + a
= a
Hence, option B is correct