When p (x) = (x3 + ax2 + 2x + a) is divided by (x + a), the remainder is
We have,
(x3 + ax2 + 2x + a)
Let, p (x) = (x3 + ax2 + 2x + a)
And, x + a = 0
x = - a
It is given that, (x + a) is a factor of p (x) so the remainder is equal to p (-a)
∴ p (-a) = (-a)3 + a (-a)2 + 2 (-a) + a
= - a3 + a3 – 2a + a
= - a
Hence, option C is correct