When p (x) = (x3 + ax2 + 2x + a) is divided by (x + a), the remainder is

We have,

(x3 + ax2 + 2x + a)


Let, p (x) = (x3 + ax2 + 2x + a)


And, x + a = 0


x = - a


It is given that, (x + a) is a factor of p (x) so the remainder is equal to p (-a)


p (-a) = (-a)3 + a (-a)2 + 2 (-a) + a


= - a3 + a3 – 2a + a


= - a


Hence, option C is correct

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