In the given figure, AC=BD.
Prove that AB=CD.
From the above figure we get that,
AC = AB + BC
BD = BC + CD
And it is given is that AC = BD
So, AB + BC = BC + CD ………….(i)
According to Euclid’s axiom, when equals are subtracted from equals, the remainders are also equal.
Subtracting BC from both side in eq(i), we get
AB + BC − BC = BC + CD − BC
AB = CD