The three vertices of ΔABC are A(1, 4), B(–2, 2) and C(3, 2). Plot these points on a graph paper and calculate the area of ΔABC.
Let the vertices of the triangle be A (1, 4), B (-2, 2) and C (3, 2)
Now, when we plot and join these points on the graph paper, we get a triangle ABC
Let the line BC intersect y-axis at D
∴ BC = BD + DC
= (2 + 3) units
= 5 units
Now, AL is drawn perpendicular to x-axis meeting BC at L
∴ Ordinate of point L = Ordinate of point C – 2
AL = AM – LM
= 4 – 2
= 2 units
Hence, area of =
=
=
= 5 units
∴ Area of the triangle ABC = 5 square units