Let the three vertices of rectangle ABCD be A (2, 2), B (-3, 2) and C (-3, 5)

Now, on plotting these points on the graph paper and by joining the points we get:

The point A lies in the first quadrant while B and C lie in the second quadrant

Let us assume D be the fourth vertex of the rectangle

∴ Abscissa of D = Abscissa of A = 2

And, Ordinate of D = Ordinate of C = 3

Hence, Coordinate of the fourth vertex, D = (2, 5)

Let y-axis cut AB and CD at point L and M respectively

∴ AB = (BL + LA)

= (3 + 2)

= 5 units

Also, BC = 5 – 2

= 3 units

∴ Area of rectangle ABCD = BC × AB

= 3 × 5

= 15 square units

Hence, the area of the rectangle ABCD is 15 square units