RS Aggarwal & V Aggarwal - Mathematics

Book: RS Aggarwal & V Aggarwal - Mathematics

Chapter: 7. Areas

Subject: Mathematics - Class 9th

Q. No. 12 of CCE Questions

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12

The base of an isosceles triangle is 16 cm and its area is 48cm2. The perimeter of the triangle is –

It is given in the question that,

Base of the triangle = 16 cm


Area of the triangle = 48 cm2


Let the height of the triangle be h


We know that,


Area of the triangle =


48 =


48 = 8 × h


h =


h = 6 cm


Now, half of the base = = 8 cm


By using Pythagoras theorem, we have


Side2 = 82 + 62


= 64 + 36


= 100


= 10 cm


Now, perimeter of the triangle = Sum of all sides


= 10 + 10 + 16


= 36 cm


Hence, option (b) is correct

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