The base of an isosceles triangle is 16 cm and its area is 48cm^{2}. The perimeter of the triangle is –

It is given in the question that,

Base of the triangle = 16 cm

Area of the triangle = 48 cm^{2}

Let the height of the triangle be h

We know that,

Area of the triangle =

48 =

48 = 8 × h

h =

h = 6 cm

Now, half of the base = = 8 cm

∴ By using Pythagoras theorem, we have

Side^{2} = 8^{2} + 6^{2}

= 64 + 36

= 100

= 10 cm

Now, perimeter of the triangle = Sum of all sides

= 10 + 10 + 16

= 36 cm

Hence, option (b) is correct

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