The base of an isosceles triangle is 16 cm and its area is 48cm2. The perimeter of the triangle is –
It is given in the question that,
Base of the triangle = 16 cm
Area of the triangle = 48 cm2
Let the height of the triangle be h
We know that,
Area of the triangle =
48 =
48 = 8 × h
h =
h = 6 cm
Now, half of the base = = 8 cm
∴ By using Pythagoras theorem, we have
Side2 = 82 + 62
= 64 + 36
= 100
= 10 cm
Now, perimeter of the triangle = Sum of all sides
= 10 + 10 + 16
= 36 cm
Hence, option (b) is correct