The difference between the semi- perimeter and the sides of a ∆ ABC are 8cm, 7cm and 5cm respectively. The area of the triangle is –

Let the semi-perimeter be s

Let the sides of the triangle be a, b and c


It is given in the question that,


s – a = 8 …(i)


s – b = 7 …(ii)


s – c = 5 …(iii)


Now, by adding (i), (ii) and (iii) we get:


(s – a) + (s – b) + (s – c) = 8 + 7 + 5


3s – a – b – c = 20


3s – (a + b + c) = 20


We know that,


s =


3s – 2s = 20


s = 20 cm


Now, area of the triangle =


=


= 20 cm2


Hence, option (c) is correct

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