The difference between the semi- perimeter and the sides of a ∆ ABC are 8cm, 7cm and 5cm respectively. The area of the triangle is –
Let the semi-perimeter be s
Let the sides of the triangle be a, b and c
It is given in the question that,
s – a = 8 …(i)
s – b = 7 …(ii)
s – c = 5 …(iii)
Now, by adding (i), (ii) and (iii) we get:
(s – a) + (s – b) + (s – c) = 8 + 7 + 5
3s – a – b – c = 20
3s – (a + b + c) = 20
We know that,
s =
∴ 3s – 2s = 20
s = 20 cm
Now, area of the triangle =
=
= 20 cm2
Hence, option (c) is correct