If the base of an isosceles triangle is 6cm and its perimeter is 16cm, then its area is 12cm^{2}.

It is given in the question that,

Base of the triangle, b = 6 cm

Equal sides of the isosceles triangle = a cm

Perimeter = 16 cm

We know that,

Perimeter = Sum of all sides

16 = a + a + 6

16 = 2a + 6

2a = 10

a =

a = 5 cm

∴ Area of an isosceles triangle =

=

= 1.5 ×

= 1.5 ×

= 1.5 × 8

= 12 cm^{2}

Hence, the given statement is true

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