If the base of an isosceles triangle is 6cm and its perimeter is 16cm, then its area is 12cm2.

It is given in the question that,

Base of the triangle, b = 6 cm


Equal sides of the isosceles triangle = a cm


Perimeter = 16 cm


We know that,


Perimeter = Sum of all sides


16 = a + a + 6


16 = 2a + 6


2a = 10


a =


a = 5 cm


Area of an isosceles triangle =


=


= 1.5 ×


= 1.5 ×


= 1.5 × 8


= 12 cm2


Hence, the given statement is true


25