If the base of an isosceles triangle is 6cm and its perimeter is 16cm, then its area is 12cm2.
It is given in the question that,
Base of the triangle, b = 6 cm
Equal sides of the isosceles triangle = a cm
Perimeter = 16 cm
We know that,
Perimeter = Sum of all sides
16 = a + a + 6
16 = 2a + 6
2a = 10
a = 
a = 5 cm
∴ Area of an isosceles triangle = 
= 
= 1.5 × 
= 1.5 × 
= 1.5 × 8
= 12 cm2
Hence, the given statement is true
25