A park in the shape of a quadrilateral ABCD has AB = 9m, BC = 12m, CD = 5 cm, AD = 8 m and c= 90°. Find the area of the park. [Given: 
= 5.9]
rom the given figure, it is clear that:
BCD is a right triangle
∴ BD = 
= 
= 
= 
= 13 m
Now, area of
= 
= 
= 
= 6 × 5 = 30 m2
Let the sides of the triangle be: a = 9 m, b = 8 m and c = 13 m
∴ s = 
= 
= 
= 15 m
Thus, by using Heron’s formula we get:
Area of 
= 
= 
= 
= 
= 
= 6 × 5.9 = 35.4 m2
∴ Area of quadrilateral ABCD = Area of 
+ Area of 
= 30 + 35.4
= 65.4 m2
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