The perimeter of an isosceles right- angled triangle having a as each of the equal sides is

It is given in the question that, equal sides of isosceles triangle is a

It is also given that, the given triangle is isosceles right-angled triangle


AC =


AC =


AC =


AC = a


We know that,


Perimeter of triangle = Sum of all sides


Perimeter = (AB + BC + AC)


= (a + a + a)


= 2a + a


= a (2 + )


Hence, option (b) is correct

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