The perimeter of an isosceles right- angled triangle having a as each of the equal sides is
It is given in the question that, equal sides of isosceles triangle is a
It is also given that, the given triangle is isosceles right-angled triangle
∴ AC =
AC =
AC =
AC = a
We know that,
Perimeter of triangle = Sum of all sides
∴ Perimeter = (AB + BC + AC)
= (a + a + a)
= 2a + a
= a (2 + )
Hence, option (b) is correct