The perimeter of an isosceles right- angled triangle having a as each of the equal sides is
It is given in the question that, equal sides of isosceles triangle is a
It is also given that, the given triangle is isosceles right-angled triangle
∴ AC = ![]()
AC = ![]()
AC = ![]()
AC = a![]()
We know that,
Perimeter of triangle = Sum of all sides
∴ Perimeter = (AB + BC + AC)
= (a + a + a
)
= 2a + a![]()
= a (2 +
)
Hence, option (b) is correct