Find the area of ABC in which BC = 8cm, AC = 15cm and AB = 17 cm. Find the length of altitude drawn on AB.
It is given in the question that,
Sides or triangle ABC is:
BC = a = 8 cm
AC = b = 15 cm
AB = c = 17 cm
We know that,
Perimeter of triangle = Sum of all sides
= a + b + c
= 8 + 15 + 17
= 40 cm
∴ s = 
= 
= 20 cm
Hence,
Area of 
= 
= 
= 
= 60 cm2
Also, Area of triangle ABC = 
60 = 
120 = 17 × Height
Height = 
= 7.06 cm
Hence, area of triangle is 60 cm2 and length of altitude is 7.06 cm
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