In the given figure ABC and DBC have the same base BC such that AB = 120m, AC = 122m, BC = 22m, BD = 24m and CD = 26m. Find the area of the shaded region. (Take = 10.25)
It is given in the question that,
AB = 120 m
AC = 122 m
BC = 22 m
BD = 24 m
And, CD = 26 m
We know that,
Perimeter of triangle = Sum of all sides
∴ Perimeter of = AB + BC + AC
= 120 + 22 + 122
= 264 m
s =
=
= 132 m
Now, Area () =
=
=
= 11 × 12 × 10
= 1320 m2
Now, in
BC = a, BD = b and CD = c
∴ Perimeter of = 22 + 24 + 26
= 72 m
s =
=
= 36 m
Hence, area ( =
=
=
= 24 × 10.25
= 246 m2
∴ Area of shaded region = Area () – Area ()
= 1320 – 246
= 1074 m2