Listen NCERT Audio Books to boost your productivity and retention power by 2X.
A point O is taken inside an equilateral ΔABC. If OL BC, OM AC and ON AB such that OL = 14 cm, OM = 10 cm and ON = 6 cm, find the area of ABC.
Let each side of be a cm
So, area () = Area () + Area () + Area ()
On taking “a” as common, we get,
= 15a cm2 (i)
As, triangle ABC is an equilateral triangle and we know that:
Area of equilateral triangle = cm2 (ii)
Now, from (i) and (ii) we get:
15 × 4 =
a = 20√3 cm
Now, putting the value of a in (i), we get
Area () = 15 × 20√3
= 300√3 cm2
Given a ABC in which
I. A, B and C are in the ratio 3: 2 :1.
II. AB , AC and BC are in the ratio 3 : 3 : 2 3 and AB = 3 3 cm.
Is ABC a right triangle?
The question give above has two Statements I and II. Answer the questions by using instructions given below:
(a) If the question can be answered by one of the given statements only and not by the other.
(b) If the question can be answered by using either statement alone.
(c) If the question can be answered by using both the statements but cannot be answered by using either statement.
(d) If the question cannot be answered even by using both the statements together.