2.2 dm3 of lead is to be drawn into a cylindrical wire 0.50 cm in diameter. The length of the wire is
Given volume of the cylindrical wire is 2.2dm3
Volume of a wire = 
1 dm = 10 cm ⇒ 0.50 cm = 0.05 dm
Volume of the wire =
1 m= 10 dm
⇒ 11.2 dm = 112 m
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