In the given figure, AB=AC and OB=OC. Then, ∠ABO: ∠ACO=?
It is given in the question that,
In ∆OAB and ∆OAC, we have
AB = AC
OB = OC
OA = OA (Common)
∴ By SSS congruence criterion
∴ ∠ABO = ∠ACO
So, ∠ABO: ∠ACO = 1: 1
Hence, option (A) is correct
10
In the given figure, AB=AC and OB=OC. Then, ∠ABO: ∠ACO=?
It is given in the question that,
In ∆OAB and ∆OAC, we have
AB = AC
OB = OC
OA = OA (Common)
∴ By SSS congruence criterion
∴ ∠ABO = ∠ACO
So, ∠ABO: ∠ACO = 1: 1
Hence, option (A) is correct