In the given figure, AE=DB, CB=EF And ∠ABC=∠FED. Then, which of the following is true?
From the given figure, we have
AE = DB
And, CB = EF
Now, AB = (AD – DB)
= (AD – AE)
DE = (AD – AE)
Now, in ∆ABC and ∆DEF we have:
AB = DE
CB = EF
∠ABC = ∠FED
∴ By SAS congruence criterion
∆ABC ≅ ∆DEF
Hence, option (A) is correct