In the given figure, BE CA and CF BA such that BE=CF. Then, which of the following is true?

From the given figure, we have

BE is perpendicular to CA


Also, CF is perpendicular to BA


And, BE = CF


Now, in ∆ABE and ∆ACF we have:


BE = CF (Given)


BEA = CFA = 90o


A = A (Common)


By AAS congruence criterion


∆ABE ACF


Hence, option (A) is correct

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